Download e-book for iPad: MATLAB Primer by KermitSigmon

By KermitSigmon

The most recent variation during this best-selling sequence, MATLABR Primer, 7th variation encompasses a variety of improvements reminiscent of adjustments to the computer, new beneficial properties for constructing M-files, the JIT accelerator, and a neater approach of uploading Java sessions. as well as the gains new to model 7.0, this ebook contains a new part on M-Lint (the new debugger for M-files), a brand new bankruptcy on calling Java from MATLAB and utilizing Java items contained in the MATLAB workspace, a brand new bankruptcy on calling Fortran from MATLAB, a brand new bankruptcy on fixing symbolic and numeric polynomials, nonlinear equations, and differential equations, and a brand new bankruptcy on telephone publishing, which replaces the "notebook" function.

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Expression first, and does not evaluate the right expression if the first expression is false. This is useful for partially-defined functions. Suppose f(x) returns a logical value but generates an error if x is zero. The expression (x~=0) && f(x) returns false if x is zero, without calling f(x) at all. The short-circuit or (||) acts similarly. It does not evaluate the right expression if the left is true. Both && and || require their operands to be scalar and convertible to logical, while & and | can operate on arrays.

Multiple conditions also possible: for n = -2:5 if n < 0 parity = 0 ; elseif rem(n,2) == 0 parity = 2 ; else parity = 1 ; end disp([n parity]) end The else and elseif are optional. If the else part is used, it must come last. 4 The switch statement The switch statement is just like the if statement. If you have one expression that you want to compare against several others, then a switch statement can be more concise than the corresponding if statement. See help switch for more information. 5 The try/catch statement Matrix computations can fail because of characteristics of the matrices that are hard to determine before doing the computation.

Since the diagonal is negative, and f is an absolute value, we should subtract f from A to preserve the sign. Type the command: A = A - diag(f) The matrix is now correct, although this works only if all of the rows need to be fixed and all diagonal entries are negative. Stop the script by selecting Debug ► Exit Debug Mode or by clicking: Clear the breakpoint. * f(i)) ; Type A=[-1 2;1 -1] and run the script. The script seems to work, but it modifies A more than is needed. Try the script on A=zeros(4), and you will see that the matrix is not modified at all, because sign(0) is zero.

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